### 6.2. `countedArray`: Parse N followed by N things

```pp.countedArray(`parser`, intExpr=None)
```

This rather specialized function creates a parser that matches some count, followed by that many occurrences of a pattern matching some `parser`, like ```"3 Moe Larry Curly"```. This function deposits a list of the values into the returned `ParseResults`, omitting the count itself. Note that the integers in this example are returned as type `str`, not type `int`.

```>>> number = pp.Word(pp.nums)
>>> print pp.countedArray(number).parseString('3 18 37 33')
[['18', '37', '33']]
>>> countedQuoted = pp.countedArray(pp.QuotedString('"'))
>>> print countedQuoted.parseString('3 "Moe" "Larry" "Curly Joe"')
[['Moe', 'Larry', 'Curly Joe']]
```

If the count is for some reason not an integer in the usual form, you can provide an `intExpr` keyword argument that specifies a parser that will match the count and return it as a Python `int`.

```>>> def octInt(toks): # Convert octal to int
...     return int(toks[0], 8)
...
>>> octal = pp.Word('01234567').setParseAction(octInt)
>>> print octal.parseString('77')
[63]
>>> print pp.countedArray(number, intExpr=octal).parseString(
...     '11 1 2 3 4 5 6 7 8 9')
[['1', '2', '3', '4', '5', '6', '7', '8', '9']]
```